{"id":187,"date":"2014-11-22T00:04:28","date_gmt":"2014-11-22T00:04:28","guid":{"rendered":"http:\/\/vk8bn.me\/info\/?p=187"},"modified":"2015-01-17T00:38:59","modified_gmt":"2015-01-17T00:38:59","slug":"l-network-impedance-matching","status":"publish","type":"post","link":"https:\/\/vk8bn.me\/info\/l-network-impedance-matching\/","title":{"rendered":"L Network Impedance matching"},"content":{"rendered":"<p>The tools required for calculating the vales in an L Network come from the following equations that can be found in the ARRL Handbook.<br \/>\nXS = QRs and Xp=Rp\/Q<br \/>\nQ=Xs\/Rs and Q=Rp\/Xp<br \/>\nRp=Rs(Q^2+1)<br \/>\nRs=Rp\/\u3016(Q\u3017^2+1)<br \/>\nQ=\u221a(RP\/Rs-1)<br \/>\nThe L network is based on a technique known as series to parallel transformations.<!--more--><br \/>\nSuppose we have measured the impedance of an antenna we have constructed with an antenna analyzer and found it to be 21 + J5\u2126. We are going to match this impedance to a 50\u2126 line.<br \/>\nWe first give the larger impedance the designation of Rp then determine the Q. We will put the +J5\u2126 aside for the moment.<br \/>\nSo Q= \u221a(50\/21-1) = 1.715<br \/>\nWe now find the parallel reactance required to be placed across the 50\u2126 .<br \/>\nXp=Rp\/Q =50\/1.715 =42.55 We now have our parallel form 50\u2126 in parallel with a 42.55\u2126 reactance. This reactance could be chosen as an inductor or a capacitor however in some circumstances the values may become quite ridiculous so try the other option. What is a 42.55\u2126 reactance? I shall choose a working frequency of 14.2MHz for my example. I am going to choose a capacitor for my reactance. The reactance of a capacitor can be calculated using the following formula C=1\/2\u220fFXc where Xc is the reactance an f in this case 14.2MHz. In our case this gives a capacitor of 260 PF.<br \/>\nNow we convert to series equivalent. Xs = QRs Rs is the 21\u2126 we are trying to match. So Xs =1.175 x 21 = 24.675\u2126. As we chose a capacitor for our parallel reactance we will now place a series inductor with a reactance of 24.675\u2126 in series to cancel the remaining reactance. The reactance of an inductor is calculated using the following equation Xs=2\u220fFL rearranging we have L= Xs\/2\u220fF. In our case at 14.2MHz this is an inductance of 276nH. Remember we put the +J5\u2126 aside now when we take it into consideration we can subtract this reactance from our required reactance. The reactance of 5 ohms we need to subtract from the 24.675\u2126 we calculated for Xs. So in fact our required reactance is actually 19.675\u2126 or an inductor of 220 nH.<br \/>\nTo summarize we place a 260PF capacitor across the 50 ohms and form an L network by placing a 220 nH inductor in series. The 21+J5\u2126 with the L network in place will have a combined impedance of 50+J0\u2126.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>The tools required for calculating the vales in an L Network come from the following equations that can be found in the ARRL Handbook. XS = QRs and Xp=Rp\/Q Q=Xs\/Rs and Q=Rp\/Xp Rp=Rs(Q^2+1) Rs=Rp\/\u3016(Q\u3017^2+1) Q=\u221a(RP\/Rs-1) The L network is based on a technique known as series to parallel transformations.<\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"jetpack_post_was_ever_published":false,"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"_jetpack_memberships_contains_paid_content":false,"footnotes":"","jetpack_publicize_message":"","jetpack_publicize_feature_enabled":true,"jetpack_social_post_already_shared":false,"jetpack_social_options":{"image_generator_settings":{"template":"highway","default_image_id":0,"font":"","enabled":false},"version":2}},"categories":[12],"tags":[],"class_list":["post-187","post","type-post","status-publish","format-standard","hentry","category-antennas"],"jetpack_publicize_connections":[],"jetpack_featured_media_url":"","jetpack_sharing_enabled":true,"jetpack_shortlink":"https:\/\/wp.me\/p8ympN-31","jetpack-related-posts":[],"_links":{"self":[{"href":"https:\/\/vk8bn.me\/info\/wp-json\/wp\/v2\/posts\/187","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/vk8bn.me\/info\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/vk8bn.me\/info\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/vk8bn.me\/info\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/vk8bn.me\/info\/wp-json\/wp\/v2\/comments?post=187"}],"version-history":[{"count":2,"href":"https:\/\/vk8bn.me\/info\/wp-json\/wp\/v2\/posts\/187\/revisions"}],"predecessor-version":[{"id":189,"href":"https:\/\/vk8bn.me\/info\/wp-json\/wp\/v2\/posts\/187\/revisions\/189"}],"wp:attachment":[{"href":"https:\/\/vk8bn.me\/info\/wp-json\/wp\/v2\/media?parent=187"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/vk8bn.me\/info\/wp-json\/wp\/v2\/categories?post=187"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/vk8bn.me\/info\/wp-json\/wp\/v2\/tags?post=187"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}